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0=208-16x^2
We move all terms to the left:
0-(208-16x^2)=0
We add all the numbers together, and all the variables
-(208-16x^2)=0
We get rid of parentheses
16x^2-208=0
a = 16; b = 0; c = -208;
Δ = b2-4ac
Δ = 02-4·16·(-208)
Δ = 13312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13312}=\sqrt{1024*13}=\sqrt{1024}*\sqrt{13}=32\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{13}}{2*16}=\frac{0-32\sqrt{13}}{32} =-\frac{32\sqrt{13}}{32} =-\sqrt{13} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{13}}{2*16}=\frac{0+32\sqrt{13}}{32} =\frac{32\sqrt{13}}{32} =\sqrt{13} $
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